The main oxygen atom in water has two lone pairs of electrons, whereas the main carbon atom in methane has actually no lone pairs. :)

lutz-heilmann.info: This is because of the presence of lone pairs ion water molecule.

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Explanation:

To calculate the hybridization, we use the formula:

" alt=" extNumber of electrons =frac12" align="absmiddle" class="latex-formula">

where, V = variety of valence electrons existing in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

For

=4" alt=" extNumber of electrons =frac12<6+2-0+0>=4" align="absmiddle" class="latex-formula">

The variety of electrons is 4 that means the hybridization will be

and the digital geomeattempt of the molecule will certainly be tetrahedral. But as tbelow are two atoms approximately the main oxygen atom, the two various other positions are lived in by the lone pair of electrons. Now, the molecular geomeattempt of the molecule becomes bent.

For

=4" alt=" extNumber of electrons =frac12<4+4-0+0>=4" align="absmiddle" class="latex-formula">

The variety of electrons is 4 that suggests the hybridization will be

and also the digital geometry of the molecule will be tetrahedral. As, all the positions roughly the central steel atom which is carbon are lived in, so no lone pair of electrons are current.

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As, the repulsions between lone pair and bond pair is even more, so the bond angle which should be 109.5° has actually decreased to an angle of 104.5° in water.