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The warm flux for a provided wall is in the x-direction and also provided as q^n = 11 W/m^2, the walls thermal conductivity is 1.7 W/mK and Also as we can check out the equation that warm flux directly counts on the temperature gradient so even more is the temperature gradient then even more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the warmth will flow inwards

Explanation:

As we understand that heat flux is provided by the formula here we know that

K = thermal conductivity currently we recognize that also we know that

K = 1.7 W/mK

now we have so temperature gradient is provided as likewise in other unit it will be same Also as we have the right to see the equation that warmth flux straight relies on the temperature gradient so more is the temperature gradient then even more will be the warmth flux.

For positive temperature gradient the heat will circulation outwards while for negative temperature gradient the warm will certainly flow inwards

5 0
7 months ago

Find the westward component of a resultant vector 85.42 unit, 23 levels W of N
Sindrei <870>

Because the angle is West of North, therefore to discover forthe westward component (horizontal component) of the vector, we usage the sinfunction:

sin θ = oppowebsite side / hypotenusage = westward component /resultant vector

So the westward component (x) is:

x = 85.42 sin 23

x = 33.38 unit

5 0
9 months ago

Rank the 6 combinations of electric charges on the basis of the electrical force acting on q1. specify pressures pointing to the rig 6 0
10 months ago

What is the number of paths via which power can circulation in a series circuit?
netineya <11>
The answer is A. Series circuits deserve to just follow one possible route.
6 0
10 months ago
If you have a mass of 55 kg and also you are standing 3 meters away from your automobile, which has actually a mass of 1233 kg, how strong is the for
QveST <7>

5.03×10¯⁷ N

Explanation:

From the question provided over, the complying with information were obtained:

Mass of the perboy (M₁) = 55 Kg

Mass of the car (M₂) = 1234 Kg

Distance apart (r) = 3 m

Gravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²

Force (F) =?

The force in between the perchild and his car deserve to be acquired as follow:

F = GM₁M₂ / r²

F = 6.673×10¯¹¹ × 55 × 1234 / 3²

F = 6.673×10¯¹¹ × 67870/ 9

F = 5.03×10¯⁷ N

Therefore, the force between the perchild and his car is 5.03×10¯⁷ N

3 0
11 months ago
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