In each situation, recognize the worth of the constant c that renders the probcapacity statement correct.

You are watching: In each case determine the value of the constant c

\$P(c le |Z|)=0.016\$

Here is my attempt:

\$P(|Z| ge c)=0.016\$

\$P(Z ge c~or~Z le -c) = 0.016 \$

\$<1-phi (c)> - phi (-c) = 0.016\$

By symmeattempt, \$1-phi (c)\$ and also \$phi (-c)\$ are equal.

\$2 phi (-c) = 0.016 suggests phi (-c) = 0.008\$.

However before, this does not bring about the correct solution. What exactly did I fix for? And just how was I actually intend to solve this question?

You started correctly: We want a merged probability of \$0.016\$ in the 2 tails \$Zge c\$ and also \$Zle -c\$. By symmetry, we desire a probcapacity of \$frac0.0162=0.008\$ in the "right tail."

Equivalently, we want \$Pr(Zle c)=1-0.008=0.992\$. Look for \$0.9992\$ in the body of your standard normal table.

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