In each situation, recognize the worth of the constant c that renders the probcapacity statement correct.
You are watching: In each case determine the value of the constant c
$P(c le |Z|)=0.016$
Here is my attempt:
$P(|Z| ge c)=0.016$
$P(Z ge c~or~Z le -c) = 0.016 $
$<1-phi (c)> - phi (-c) = 0.016$
By symmeattempt, $1-phi (c)$ and also $phi (-c)$ are equal.
$2 phi (-c) = 0.016 suggests phi (-c) = 0.008$.
However before, this does not bring about the correct solution. What exactly did I fix for? And just how was I actually intend to solve this question?
You started correctly: We want a merged probability of $0.016$ in the 2 tails $Zge c$ and also $Zle -c$. By symmetry, we desire a probcapacity of $frac0.0162=0.008$ in the "right tail."
Equivalently, we want $Pr(Zle c)=1-0.008=0.992$. Look for $0.9992$ in the body of your standard normal table.
Thanks for contributing a solution to lutz-heilmann.infoematics Stack Exchange!Please be certain to answer the question. Provide details and share your research!
But avoid …Asking for assist, clarification, or responding to other answers.Making statements based on opinion; earlier them up with recommendations or individual experience.
Use lutz-heilmann.infoJax to format equations. lutz-heilmann.infoJax referral.
See more: Pretty Little Liars Who Said It, Take Our Quote Quiz
To learn even more, check out our tips on composing great answers.
Message Your Answer Discard
Not the answer you're looking for? Browse various other questions tagged probcapacity statistics normal-circulation or ask your own question.
website style / logo © 2021 Stack Exchange Inc; user contributions licensed under cc by-sa. rev2021.10.15.40479