Two attributes, f andg, are explained listed below. Which of these statementsabout f and also g is true? So they definedattribute f as kind of a typical linearequation appropriate over here. And this right over right here is g. So this best overright here is g of x. And that additionally looksfavor a straight function. We check out it's a kind of adownward sloping line. So let's look at our choicesand also see which of these are true. f and g are both boosting, andf is enhancing much faster than g. Well, when I look at g--Well, first of all, g is absolutely decreasing. So we already knowthat that's false. And f is also decreasing. We check out here it hasan unfavorable slope. Eincredibly time we move forward3 in the x direction, we're going to move down 7in the vertical direction. So neither of theseare boosting so that's absolutely not right. f and g are both raising. Well, that'sdefinitely not ideal. So we know that both fand also g are decreasing. So this first option saysthey're both decreasing, and also g is decreasing quicker than f. So let's view whatthe slope on g is. So the slope on g is eextremely timewe move 1 in the x direction, positive 1 in thex direction, we relocate down 2 in the y direction. So for g of x, if we wereto compose our readjust in y over our adjust in x-- whichis our slope-- our adjust in y over adjust in x, as soon as wemove one in the x direction, positive 1 in thex direction, we relocate down 2 in the y direction. So our change in y overreadjust in x is negative 2. So g has a slope of negative 2. f has a slope of negative 7/3. Negative 7/3 is the samething as negative 2 and also 1/3. So f's slope is more negative. So it is decreasing quicker. So g is not decreasing fasterthan f. f is decreasing faster than g. So this is not right. And then we have this choice--f and also g are both decreasing, and also f is decreasingmuch faster than g. This is ideal, ideal over right here. We have actually this last choice-- g isincreasing yet f is decreasing. We know that's not true.g is actually decreasing.

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Comparing linear functions: exact same price of change
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