A ladder leans against a wall surface at a point \$8\$ feet over the ground. The bottom of the ladder rests \$2\$ feet ameans from the wall. How long is the ladder?  Use Pythagorean Theorem: \$a^2 + b^2=c^2\$

Let \$a=2\$, \$b=8\$ and also \$c\$ be the length of the ladder. Plug in your worths and settle for C.

You are watching: A ladder is leaning against a wall From what I think is the question this is just a basic application of the Pythagoras theorem

\$a^2+b^2=c^2\$

Wbelow \$c\$ is the longest side and also \$b\$ and also \$a\$ are the various other sides. So in your question, we understand that \$a=2\$ and also \$b=8\$ so we need to fix for \$c\$. We have the right to plug the numbers in to acquire the answer

\$2^2+8^2=c^2=68\$ so \$c=sqrt68\$ feet I believe \$\$ an heta = 8/2=4suggests heta= an^-14\$\$

Keep in mind that\$\$sec heta = h/2\$\$\$\$2sec heta = h\$\$\$\$h=2sqrt an^2 heta+1=2sqrt an^2( an^-14)+1=2sqrt4^2+1=2sqrt17\$\$ Thanks for contributing a solution to lutz-heilmann.infoematics Stack Exchange!

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